(A) Rosenmund reduction is the hydrogenation of an acid chloride $(R-COCl)$ to an aldehyde $(R-CHO)$ using a palladium catalyst poisoned with barium s

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$R-COCl + H_2 \xrightarrow{Pd/BaSO_4} R-CHO + HCl$

(A) Rosenmund reduction is the hydrogenation of an acid chloride $(R-COCl)$ to an aldehyde $(R-CHO)$ using a palladium catalyst poisoned with barium sulfate $(Pd/BaSO_4)$.The reaction is:$R-COCl + H_2 \xrightarrow{Pd/BaSO_4} R-CHO + HCl$Therefore,option $A$ represents the Rosenmund reduction.

Class 12 Chemistry 1 Aldehydes, Ketones and Carboxylic Acids: Aldehydes and Ketones Preparation

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Which of the following is Rosenmund reduction?

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A
$R-COCl + H_2 \xrightarrow{Pd/BaSO_4} R-CHO + HCl$
B
$R-C \equiv N + 2[H]$ $\xrightarrow[dil. HCl]{SnCl_2} R-CH=NH \cdot HCl$ $\xrightarrow{H_3O^+} R-CHO + NH_4Cl$
C
$R-CHO \xrightarrow[\Delta]{H_2N-NH_2, KOH/\text{ethylene glycol}} R-CH_3 + N_2$
D
$R-CO-R + 4[H] \xrightarrow[\Delta]{Zn-Hg/\text{conc. } HCl} R-CH_2-R + H_2O$