Which of the following is a spin-free complex | vedclass

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(A) spin-free complex (also known as a high-spin complex) is one where the electrons are arranged to maximize the number of unpaired electrons.In $[Fe

Vedclass · Accepted Answer

$[Fe(H_2O)_6]Cl_2$

Vedclass · Answer

(A) spin-free complex (also known as a high-spin complex) is one where the electrons are arranged to maximize the number of unpaired electrons.In $[Fe(H_2O)_6]Cl_2$,the central metal ion is $Fe^{2+}$,which has a $d^6$ configuration.$H_2O$ is a weak field ligand,so it does not cause pairing of electrons in the $d$-orbitals.Thus,the electrons are arranged as $t_{2g}^4 e_g^2$,resulting in $4$ unpaired electrons,making it a spin-free complex.In contrast,$CN^-$ and $CO$ are strong field ligands that cause pairing of electrons,leading to low-spin (spin-paired) complexes.Therefore,$[Fe(H_2O)_6]Cl_2$ is the correct answer.

Which of the following is a spin-free complex?

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