Which of the following is the strongest Brons | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Bronsted base is a substance that can accept a proton $(H^+)$. The strength of a base depends on the availability of the lone pair of electrons on

Vedclass · Accepted Answer

Pyrrolidine

Vedclass · Answer

(D) Bronsted base is a substance that can accept a proton $(H^+)$. The strength of a base depends on the availability of the lone pair of electrons on the nitrogen atom.$1$. In $A$ (Aniline),the lone pair on nitrogen is delocalized into the benzene ring due to resonance,making it less available for protonation.$2$. In $B$ (Diphenylamine),the lone pair is delocalized into two benzene rings,making it even less basic than aniline.$3$. In $C$ (Pyrrole),the lone pair on nitrogen is involved in the aromatic sextet (it is part of the $6\pi$ electron system),so it is not available for protonation.$4$. In $D$ (Pyrrolidine),the nitrogen atom is $sp^3$ hybridized and the lone pair is localized (not involved in resonance). This makes the lone pair readily available for donation to a proton,making it the strongest base among the given options.

Which of the following is the strongest Bronsted base?

Similar Questions

Why is benzene diazonium chloride not stored and is used immediately after its preparation?

Identify the $CORRECT$ decreasing order of solubilities of alcohols,alkanes,and amines in water having comparable molar mass.

Identify the products $y$ and $x$ in the following reaction sequence:
$C_6H_5CONH_2 \xrightarrow{NaOBr} y$
$C_6H_5CONH_2 \xrightarrow[(ii) H_3O^+]{(i) C_6H_5SO_2Cl / py, \Delta} x$

$C_2H_5Cl$ $\xrightarrow{KCN} X$ $\xrightarrow{H_2 / \text{Catalyst}} Y$ $\xrightarrow{CHCl_3 / KOH} Z$
What is '$Z$' in the above sequence of reactions?

The major product formed in the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module