Which of the following is the correct order f | vedclass

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(C) The correct order of bond angle is $H_3Te^{+} < H_3Se^{+} < H_3S^{+} < H_3O^{+}$.Explanation:$(a)$ In $NH_3$ group hydrides,as the electronegativi

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$H_3Te^{+} < H_3Se^{+} < H_3S^{+} < H_3O^{+}$

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(C) The correct order of bond angle is $H_3Te^{+} Explanation:$(a)$ In $NH_3$ group hydrides,as the electronegativity of the central atom decreases,the bond angle decreases: $NH_3 > PH_3 > AsH_3 > SbH_3$.$(b)$ In $OF_2$ and $H_2O$,the bond angle is affected by the electronegativity of the surrounding atoms. The correct order is $OF_2 $(c)$ In $H_3X^{+}$ species,as the electronegativity of the central atom $X$ increases,the bond angle increases. Thus,$H_3Te^{+} $(d)$ In $BX_3$ molecules,the bond angle is $120^{\circ}$ for all due to $sp^2$ hybridization,so $BF_3 = BCl_3 = BBr_3 = BI_3$.

$A$. Trigonal planar	$I$. $PCl_5$
$B$. Tetrahedral	$II$. $SF_6$
$C$. Trigonal bipyramidal	$III$. $BF_3$
$D$. Octahedral	$IV$. $CCl_4$

Which of the following is the correct order for increasing bond angle?

Similar Questions

Which of the following statements is incorrect?

The equatorial and axial $P-Cl$ bond lengths (in $pm$) respectively in $PCl_5$ are:

Match the molecular geometries in List-$I$ with their corresponding molecules in List-$II$:
$A$. Trigonal planar $I$. $PCl_5$
$B$. Tetrahedral $II$. $SF_6$
$C$. Trigonal bipyramidal $III$. $BF_3$
$D$. Octahedral $IV$. $CCl_4$

The correct match for $A, B, C, D$ is:

The molecular shapes of $SF_4$,$CF_4$,and $XeF_4$ are:

Which of the following compounds is not linear?

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