Which of the following is the strongest reduc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The strength of a reducing agent is determined by its standard electrode potential $(E^{\circ})$. Lower (more negative) $E^{\circ}$ values indicat

Vedclass · Accepted Answer

$K$

Vedclass · Answer

(A) The strength of a reducing agent is determined by its standard electrode potential $(E^{\circ})$. Lower (more negative) $E^{\circ}$ values indicate a stronger tendency to undergo oxidation,making the species a stronger reducing agent. The standard reduction potentials are: $K^+/K = -2.93 \ V$ $Mg^{2+}/Mg = -2.37 \ V$ $Al^{3+}/Al = -1.66 \ V$ $Ag^+/Ag = +0.80 \ V$ Since $K$ has the most negative $E^{\circ}$ value,it is the strongest reducing agent among the given options.

Element	$M^{3+}/M$	$M^{+}/M$
$Al$	$-1.66$	$+0.55$
$Tl$	$+1.26$	$-0.34$

Which of the following is the strongest reducing agent?

Similar Questions

Why does copper not replace hydrogen from acids?

The standard reduction potentials at $25^o \text{C}$ for $Li^{+}/Li$,$Ba^{2+}/Ba$,$Na^{+}/Na$,and $Mg^{2+}/Mg$ are $-3.05 \ V$,$-2.73 \ V$,$-2.71 \ V$,and $-2.37 \ V$ respectively. Which of the following is the strongest oxidizing agent?

The standard hydrogen electrode has a zero electrode potential because .....

How would you determine the standard electrode potential of the system $Mg^{2+} | Mg$?

Consider the following standard electrode potentials ($E^0$ in volts) in aqueous solution. Based on this data,which of the following statements is correct?
Element $M^{3+}/M$ $M^{+}/M$
$Al$ $-1.66$ $+0.55$
$Tl$ $+1.26$ $-0.34$

Vedclass Test Series

Exam Paper Generator

Online Exam Module