Which of the following is the strongest reduc | vedclass

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(D) The reducing power of oxides of group $16$ elements decreases down the group.This is because the stability of the $+4$ oxidation state increases d

Vedclass · Accepted Answer

$SO_2$

Vedclass · Answer

(D) The reducing power of oxides of group $16$ elements decreases down the group.This is because the stability of the $+4$ oxidation state increases down the group due to the inert pair effect.$SO_2$ acts as a reducing agent because $S$ can easily be oxidized from $+4$ to $+6$ oxidation state.In contrast, $TeO_2$ is more stable in the $+4$ state and does not easily oxidize to $+6$.Therefore, $SO_2$ is the strongest reducing agent among the given options.

Which of the following is the strongest reducing agent?

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