Which of the following isotopes is likely to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The stability of an isotope is often related to its neutron-to-proton ratio ($n/p$ ratio).For $_{30}Zn^{64}$,the number of protons $(p)$ is $30$ a

Vedclass · Accepted Answer

$_{30}Zn^{64}$

Vedclass · Answer

(C) The stability of an isotope is often related to its neutron-to-proton ratio ($n/p$ ratio).For $_{30}Zn^{64}$,the number of protons $(p)$ is $30$ and the number of neutrons $(n)$ is $64 - 30 = 34$.The $n/p$ ratio is $\frac{34}{30} \approx 1.13$.For $_{30}Zn^{66}$,$n = 36$,so $n/p = \frac{36}{30} = 1.2$.For $_{30}Zn^{71}$,$n = 41$,so $n/p = \frac{41}{30} \approx 1.37$.Since $_{30}Zn^{64}$ has the lowest $n/p$ ratio among the given options and is a naturally occurring stable isotope of Zinc,it is the most stable.

Which of the following isotopes is likely to be most stable?

Similar Questions

Assertion : Nuclear binding energy per nucleon is in the order $_4^9Be > \,_3^7Li > \,_2^4He$.
Reason : Binding energy per nucleon increases linearly with the difference in the number of neutrons and protons.

Let $m_p$ be the mass of a proton,$m_n$ that of a neutron,$M_1$ that of a $_{10}^{20}Ne$ nucleus,and $M_2$ that of a $_{20}^{40}Ca$ nucleus. Then:

In the radioactive disintegration series ${}_{90}^{232}Th \rightarrow {}_{82}^{208}Pb$ involving $\alpha$ and $\beta$ decay,the total number of $\alpha$ and $\beta$ particles emitted are:

The isotopic mass of ${}_{3}^{7}Li$ is $7.016005 \ u$ and those of the $H$ atom and neutron are respectively $1.007825 \ u$ and $1.008665 \ u$. Then,the binding energy of the ${}_{3}^{7}Li$ nucleus is: (in $MeV$)

In a nuclear explosion, the energy is released in the form of

Vedclass Test Series

Exam Paper Generator

Online Exam Module