Which of the following metal ions will form c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $Cu^{2+}$ ($3d^9$ configuration) forms complexes with the same magnetic moment and geometry irrespective of the nature of the ligand.The electroni

Vedclass · Accepted Answer

$Cu^{2+}$

Vedclass · Answer

(C) $Cu^{2+}$ ($3d^9$ configuration) forms complexes with the same magnetic moment and geometry irrespective of the nature of the ligand.The electronic configuration of $Cu^{2+}$ is $[Ar] 3d^9$. The $3d$ subshell contains one unpaired electron.Since the $3d$ subshell is almost completely filled,the incoming ligands cannot cause any pairing or redistribution of electrons in the $3d$ orbitals. Therefore,the number of unpaired electrons remains $1$ (magnetic moment $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$) regardless of whether the ligand is strong or weak.Furthermore,the geometry of $Cu^{2+}$ complexes is typically determined by the number of ligands (e.g.,square planar for $4$ ligands due to Jahn-Teller distortion),which remains consistent for a given coordination number.

Which of the following metal ions will form complexes with the same magnetic moment and geometry irrespective of the nature of ligands?

Similar Questions

The isomerism exhibited by $[Co(NH_3)_5(SO_4)]Br$ and $[Co(NH_3)_5(SO_4)]Cl$ is of the ........ type.

Assertion : $[Co(NO_2)_3(NH_3)_3]$ does not show optical isomerism.
Reason : It has a plane of symmetry.

Consider the following complex ions,$P$,$Q$ and $R$.
$P = [FeF_6]^{3-}$,$Q = [V(H_2O)_6]^{2+}$ and $R = [Fe(H_2O)_6]^{2+}$.
The correct order of the complex ions,according to their spin-only magnetic moment values (in $B.M.$) is

Which of the following complexes exhibits optical isomerism?

$[Co(NH_3)_5Cl]SO_4$ and $[Co(NH_3)_5SO_4]Cl$ are which type of isomers?

Vedclass Test Series

Exam Paper Generator

Online Exam Module