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(D) nodal plane is a plane where the probability of finding an electron is zero. For the antibonding molecular orbital $ \pi_{2px}^* $,there are two n

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$ \pi_{2px}^* $

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(D) nodal plane is a plane where the probability of finding an electron is zero. For the antibonding molecular orbital $ \pi_{2px}^* $,there are two nodal planes: one is the nodal plane of the atomic $ p_x $ orbitals (the $ yz $-plane),and the other is the nodal plane perpendicular to the internuclear axis passing through the center of the bond (due to the antibonding nature). Thus,$ \pi_{2px}^* $ has two nodal planes.

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

Which of the following molecular orbitals has two nodal planes?

Similar Questions

Match the following:

Pair of species Identical property

$A$. $B_2 \& O_2$ $P$. Bond order $= 2.5$

$B$. $Be_2 \& H_2^{2-}$ $Q$. Paramagnetic nature

$C$. $N_2^{+} \& N_2^{-}$ $R$. Diamagnetic nature

$D$. $O_2^{+} \& O_2^{-}$ $S$. Doesn't exist

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