Which of the following molecular species is n | vedclass

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(D) To determine the geometry of the given species,we use the $VSEPR$ theory:$1$. $(CN)_2$ (Cyanogen): The structure is $N \equiv C-C \equiv N$. The c

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$S_3^{2-}$

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(D) To determine the geometry of the given species,we use the $VSEPR$ theory:$1$. $(CN)_2$ (Cyanogen): The structure is $N \equiv C-C \equiv N$. The carbon atoms are $sp$ hybridized,resulting in a linear geometry.$2$. $OCN^{-}$ (Cyanate ion): The structure is $[O=C=N]^{-}$. The central carbon atom is $sp$ hybridized with no lone pairs,resulting in a linear geometry.$3$. $XeF_2$: The central $Xe$ atom has $2$ bond pairs and $3$ lone pairs. According to $VSEPR$ theory,the lone pairs occupy the equatorial positions of a trigonal bipyramid to minimize repulsion,resulting in a linear molecular geometry.$4$. $S_3^{2-}$ (Trisulfide ion): The central sulfur atom has $2$ bond pairs and $2$ lone pairs (total $4$ electron pairs,$sp^3$ hybridization). Due to the presence of $2$ lone pairs,the geometry is bent (angular),similar to $H_2O$.Therefore,$S_3^{2-}$ is not linear.

Which of the following molecular species is not linear?

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