Which of the following molecules has a regula | vedclass

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(A) $1$. $SiCl_4$: The central atom $Si$ has $4$ valence electrons and forms $4$ bonds with $Cl$ atoms. It undergoes $sp^3$ hybridization with $0$ lon

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$SiCl_4$

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(A) $1$. $SiCl_4$: The central atom $Si$ has $4$ valence electrons and forms $4$ bonds with $Cl$ atoms. It undergoes $sp^3$ hybridization with $0$ lone pairs,resulting in a regular tetrahedral geometry.$2$. $SF_4$: The central atom $S$ has $6$ valence electrons,forms $4$ bonds,and has $1$ lone pair. It undergoes $sp^3d$ hybridization,resulting in a see-saw geometry (distorted).$3$. $BrF_5$: The central atom $Br$ has $7$ valence electrons,forms $5$ bonds,and has $1$ lone pair. It undergoes $sp^3d^2$ hybridization,resulting in a square pyramidal geometry (distorted).$4$. $XeF_4$: The central atom $Xe$ has $8$ valence electrons,forms $4$ bonds,and has $2$ lone pairs. It undergoes $sp^3d^2$ hybridization,resulting in a square planar geometry (distorted due to lone pairs).$5$. Therefore,only $SiCl_4$ has a regular geometry.

Which of the following molecules has a regular geometry as expected?

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