Which of the following molecules has a square | vedclass

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(C) To determine the geometry,we calculate the steric number using the formula: $Steric \ Number = \frac{1}{2} (V + M - C + A)$,where $V$ is the numbe

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$XeOF_4$

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(C) To determine the geometry,we calculate the steric number using the formula: $Steric \ Number = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $XeOF_4$:$V = 8$ (for $Xe$),$M = 4$ (for $F$),$O$ is divalent (not counted in $M$).$Steric \ Number = \frac{1}{2} (8 + 4) = 6$.$A$ steric number of $6$ corresponds to $sp^3d^2$ hybridization,which has an octahedral electron geometry.With $5$ bonding pairs ($4$ $Xe-F$ and $1$ $Xe=O$) and $1$ lone pair,the molecular geometry is square pyramidal.

Which of the following molecules has a square pyramidal geometry?

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