Which of the following options is correct for | vedclass

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(C) In the given graph, the $t$-axis represents time and the $s$-axis represents position (displacement).For any graph, the slope is given by $\frac{d

Vedclass · Accepted Answer

Average velocity is zero.

Vedclass · Answer

(C) In the given graph, the $t$-axis represents time and the $s$-axis represents position (displacement).For any graph, the slope is given by $\frac{dy}{dx}$. Here, the slope is $\frac{dt}{ds} = \frac{1}{v}$, where $v$ is the velocity.At point $D$, the position $s$ returns to $0$ at some time $t > 0$. Since the object starts from the origin ($s=0$ at $t=0$) and returns to the origin ($s=0$ at $t=t_D$), the net displacement is $\Delta s = s_{final} - s_{initial} = 0 - 0 = 0$.Average velocity is defined as $	ext{Average velocity} = \frac{	ext{Total Displacement}}{	ext{Total Time}} = \frac{0}{t_D} = 0$.Therefore, option $C$ is correct.

Which of the following options is correct for an object having a straight-line motion represented by the following graph?

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