Which of the following orders is correct?

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(C) For $(a)$,the ionic size of isoelectronic species increases as the nuclear charge decreases: $Ca^{2+} (20) < K^{+} (19) < S^{2-} (16) < P^{3-} (15

Vedclass · Accepted Answer

$Al_{(aq.)}^{3+} > Mg_{(aq.)}^{2+} > Na_{(aq.)}^{+}$: Hydrated size

Vedclass · Answer

(C) For $(a)$,the ionic size of isoelectronic species increases as the nuclear charge decreases: $Ca^{2+} (20) For $(b)$,in aqueous solution,the extent of hydration decreases as the size of the cation increases $(Na^{+} > K^{+} > Rb^{+} > Cs^{+})$. Smaller hydrated ions move faster,but electrical conductance depends on the mobility of the hydrated ion. The order of ionic mobility and conductance in aqueous solution is $Cs^{+} > Rb^{+} > K^{+} > Na^{+}$. Thus,the given order is incorrect.For $(c)$,the extent of hydration is directly proportional to the charge density. $Al^{3+}$ has the highest charge density,followed by $Mg^{2+}$ and $Na^{+}$. Therefore,the hydrated size order is $Al_{(aq.)}^{3+} > Mg_{(aq.)}^{2+} > Na_{(aq.)}^{+}$. This is correct.For $(d)$,the extent of hydration for anions is $F^{-} > Cl^{-} > Br^{-} > I^{-}$. Consequently,the hydrated size is $F^{-} > Cl^{-} > Br^{-} > I^{-}$. Ionic mobility is inversely proportional to hydrated size,so the order is $I_{(aq.)}^{-} > Br_{(aq.)}^{-} > Cl_{(aq.)}^{-} > F_{(aq.)}^{-}$. Thus,the given order is incorrect.

Ion	Radius $(pm)$
$Q^{a+}$	$53$
$X^{b+}$	$66$
$Y^{c+}$	$40$
$Z^{d+}$	$100$

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