Which of the following orders is not correct?

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(D) Let us analyze each option:$A$: Solubility of alkaline earth metal sulfates decreases down the group due to the decrease in hydration energy being

Vedclass · Accepted Answer

$PF_3 < PH_3$ (dipole moment)

Vedclass · Answer

(D) Let us analyze each option:$A$: Solubility of alkaline earth metal sulfates decreases down the group due to the decrease in hydration energy being more significant than the decrease in lattice energy. Thus,$BeSO_4 > MgSO_4 > CaSO_4 > SrSO_4 > BaSO_4$ is correct.$B$: Bond order of $N_2$ is $3$,$N_2F_2$ is $2$,and $N_2O_4$ is $1$. Since bond length is inversely proportional to bond order,the order $N_2 $C$: $SF_4$ has $1$ lone pair,$ICl_3$ has $2$ lone pairs,and $XeF_2$ has $3$ lone pairs. The order $1 $D$: In $PF_3$,the dipole moment of $P-F$ bonds and the lone pair are in the same direction,leading to a higher dipole moment. In $PH_3$,the electronegativity difference between $P$ and $H$ is very small,and the lone pair effect is opposed by the bond dipoles. Thus,$PH_3 < PF_3$ is the correct order. Therefore,the given order $PF_3 < PH_3$ is incorrect.

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