Which of the following orders of bond length | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Bond length is inversely proportional to bond order.
$1$. For $CO$ (bond order $3$) and $CO^{+}$ (bond order $2.5$),the bond length order is $CO

Vedclass · Accepted Answer

$CO < CO^{+}$

Vedclass · Answer

(A) Bond length is inversely proportional to bond order.
$1$. For $CO$ (bond order $3$) and $CO^{+}$ (bond order $2.5$),the bond length order is $CO < CO^{+}$. This is correct.
$2$. For $Si-Si$ and $C-C$,$Si-Si$ bond length is greater due to the larger atomic size of $Si$ compared to $C$.
$3$. For $C=C$ and $C=N$,$C=C$ bond length is greater than $C=N$ due to the smaller atomic radius of $N$ compared to $C$.
$4$. For $H_2O_2$ and $O_2F_2$,the $O-O$ bond length in $H_2O_2$ $(1.48 \ \mathring{A})$ is greater than in $O_2F_2$ $(1.22 \ \mathring{A})$ due to the high electronegativity of $F$ atoms reducing the bond length.
Thus,option $A$ is correct.

Which of the following orders of bond length is correct?

Similar Questions

The total number of lone pairs of electrons on oxygen atoms of ozone $(O_3)$ is $...........$.

Compare $\pi$-bond strength between $B$ and $N$ in the following compounds: $(I)$ $((CH_3)_3Si)_2N^{-}BH_2$ and $(II)$ $((CH_3)_3C)_2N^{-}BH_2$.

Observe the following statements:
$i$. The dipole moment of $NH_3$ is higher than the dipole moment of $NF_3$.
$ii$. The dipole moment of chloroform $(CHCl_3)$ is zero.
$iii$. Covalent bond character in $NaCl$ is more compared to $CuCl$.

The Born-Haber cycle can be used to estimate:

If compound $MX_4$ is non-polar and has no lone pair at the central atom,then the bond angle $\angle XMX$ in the compound may be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module