Which of the following pairs of species has t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To calculate the percentage of carbon,use the formula: $	ext{Percentage of C} = \frac{	ext{Total mass of C}}{	ext{Molar mass of compound}} 	im

Vedclass · Accepted Answer

$CH_3COOH$ and $C_6H_{12}O_6$

Vedclass · Answer

(D) To calculate the percentage of carbon,use the formula: $	ext{Percentage of C} = \frac{	ext{Total mass of C}}{	ext{Molar mass of compound}} 	imes 100$. For $CH_3COOH$ $(C_2H_4O_2)$: Molar mass = $2(12) + 4(1) + 2(16) = 60 \ g/mol$. Percentage of $C$ = $\frac{24}{60} 	imes 100 = 40\%$. For $C_6H_{12}O_6$: Molar mass = $6(12) + 12(1) + 6(16) = 180 \ g/mol$. Percentage of $C$ = $\frac{72}{180} 	imes 100 = 40\%$. Since both compounds have $40\%$ carbon,the correct pair is $CH_3COOH$ and $C_6H_{12}O_6$.

Which of the following pairs of species has the same percentage of carbon?

Similar Questions

An organic compound contains carbon,hydrogen,and oxygen. Its elemental analysis gave $C = 38.71 \%$ and $H = 9.67 \%$. The empirical formula of the compound would be:

$A$ gas is found to contain $2.8 \ g$ of nitrogen and $3.2 \ g$ of oxygen. The simplest formula of the compound is:

An organic compound has an empirical formula of $CH_2O$ and a molecular mass of $90$. What is its molecular formula? $(C = 12, H = 1, O = 16)$

The molecular formula of a compound is $X_4O_6$. If $10 \ g$ of the compound contains $5.62 \ g$ of $X$,what is the approximate atomic mass of $X$ in $amu$?

Empirical formula of a compound is $CH_2O$ and its vapour density is $30$. The molecular formula of the compound is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module