Which of the following pairs of linear equations has a unique solution,no solution,or infinitely many solutions? In case there is a unique solution,find it by using the cross-multiplication method.
$x - 3y - 3 = 0$
$3x - 9y - 2 = 0$

(B) Given equations are:
$x - 3y - 3 = 0$ ... $(1)$
$3x - 9y - 2 = 0$ ... $(2)$
Comparing these with the standard form $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$,we get:
$a_1 = 1, b_1 = -3, c_1 = -3$
$a_2 = 3, b_2 = -9, c_2 = -2$
Now,calculating the ratios:
$\frac{a_1}{a_2} = \frac{1}{3}$
$\frac{b_1}{b_2} = \frac{-3}{-9} = \frac{1}{3}$
$\frac{c_1}{c_2} = \frac{-3}{-2} = \frac{3}{2}$
Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$,the lines represented by these equations are parallel to each other.
Therefore,the system of equations has no solution.