Which of the following planar complex is diam | vedclass

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(A) $1$. $A$ planar complex (square planar) typically involves $d^{sp^2}$ hybridization,which is diamagnetic if all electrons are paired.$2$. $[Ni(gly

Vedclass · Accepted Answer

$[Ni(gly)_2]$

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(A) $1$. $A$ planar complex (square planar) typically involves $d^{sp^2}$ hybridization,which is diamagnetic if all electrons are paired.$2$. $[Ni(gly)_2]$ is a square planar complex where $Ni^{2+}$ has a $d^8$ configuration. The glycinate ligand is a strong field ligand,causing pairing of electrons,making it diamagnetic.$3$. $[Ni(gly)_2]$ exhibits geometrical isomerism (cis and trans forms) because it is a $MA_2B_2$ type complex (where gly is a bidentate ligand acting as $AB$ type).$4$. $[Pt(NH_3)_3Cl]^+$ is square planar but does not show stereoisomerism.$5$. $[Co(H_2O)_3Cl_3]$ and $[Co(en)_3]^{3+}$ are octahedral complexes,not planar.

List-$I$	List-$II$
$(a).$ $[Co(NH_3)_6][Cr(CN)_6]$	$(i).$ Linkage isomerism
$(b).$ $[Co(NH_3)_3(NO_2)_3]$	$(ii).$ Solvate isomerism
$(c).$ $[Cr(H_2O)_6]Cl_3$	$(iii).$ Coordination isomerism
$(d).$ $cis-[CrCl_2(ox)_2]^{3-}$	$(iv).$ Optical isomerism

Which of the following planar complex is diamagnetic and shows stereo isomerism?

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