Which of the following reactions give H_2 as | vedclass

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(C) Let us analyze each reaction:$I) 2NaBH_4 + I_2 \longrightarrow 2NaI + B_2H_6 + H_2$. This reaction produces $H_2$.$II) B_2H_6 + 2N(CH_3)_3 \longri

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$I$ & $III$ only

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(C) Let us analyze each reaction:$I) 2NaBH_4 + I_2 \longrightarrow 2NaI + B_2H_6 + H_2$. This reaction produces $H_2$.$II) B_2H_6 + 2N(CH_3)_3 \longrightarrow 2BH_3 \cdot N(CH_3)_3$. This is an adduct formation reaction and does not produce $H_2$.$III) 2Al + 2NaOH + 6H_2O \longrightarrow 2Na[Al(OH)_4] + 3H_2$. This reaction produces $H_2$.$IV) 2BF_3 + 6NaH \longrightarrow B_2H_6 + 6NaF$. This reaction does not produce $H_2$.Therefore,only reactions $I$ and $III$ produce $H_2$ as a product.

Which of the following reactions give $H_2$ as one of the products? (Reactions are not balanced)
$I) NaBH_4 + I_2 \longrightarrow$
$II) B_2H_6 + N(CH_3)_3 \longrightarrow$
$III) Al + NaOH + H_2O \longrightarrow$
$IV) BF_3 + NaH \longrightarrow$

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Which of the following reactions give $H_2$ as one of the products? (Reactions are not balanced)$I) NaBH_4 + I_2 \longrightarrow$$II) B_2H_6 + N(CH_3)_3 \longrightarrow$$III) Al + NaOH + H_2O \longrightarrow$$IV) BF_3 + NaH \longrightarrow$