Which of the following reactions represents the Rosenmund reduction?
- A$R - CO - Cl \xrightarrow{H_2, Pd-BaSO_4} R - CHO + HCl$
- B$R - CN \xrightarrow{SnCl_2, HCl, H_3O^+} R - CHO + NH_4Cl$
- C$R - CHO \xrightarrow{Zn-Hg, conc. HCl, \Delta} R - CH_3 + H_2O$
- D$R - CO - R \xrightarrow{i) H_2N-NH_2, ii) KOH, HO-CH_2-CH_2-OH, \Delta} R - CH_2 - R$
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Similar Questions
Which among the following reactions does not correctly match with its reagent?
In the following sequence of reactions,what is the end product $(D)$?
$C_2H_5Br$ $\xrightarrow{KCN} A$ $\xrightarrow{H_3O^{+}} B$ $\xrightarrow{LiAlH_4} C$ $\xrightarrow[573 \ K]{Cu} D$.
$C_2H_5Br$ $\xrightarrow{KCN} A$ $\xrightarrow{H_3O^{+}} B$ $\xrightarrow{LiAlH_4} C$ $\xrightarrow[573 \ K]{Cu} D$.
Statement-$I$: Reduction of ester by $DIBAL-H$ followed by hydrolysis gives aldehyde.
Statement-$II$: Oxidation of benzyl alcohol with aqueous $KMnO_4$ leads to the formation of benzaldehyde.
Among the above statements,identify the correct statement.
Statement-$II$: Oxidation of benzyl alcohol with aqueous $KMnO_4$ leads to the formation of benzaldehyde.
Among the above statements,identify the correct statement.
MediumKCET 2025
View SolutionThe major products $P$ and $Q$ in the following reactions are:
$C_6H_5-CH=NOH$ $\xrightarrow{(i) (CH_3CO)_2O} P$ $\xrightarrow{(i) CH_3MgI, (ii) H_3O^+} Q$
$C_6H_5-CH=NOH$ $\xrightarrow{(i) (CH_3CO)_2O} P$ $\xrightarrow{(i) CH_3MgI, (ii) H_3O^+} Q$
DifficultTS EAMCET 2020
View SolutionThe reagents used in the Etard reaction $(I)$ and the Stephen reaction $(II)$ are:
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