Which of the following reactions will be affected by increasing the pressure? Also,mention whether the change will cause the reaction to proceed in the forward or backward direction.
$(i)$ $COCl_{2(g)} \longleftrightarrow CO_{(g)} + Cl_{2(g)}$
$(ii)$ $CH_{4(g)} + 2S_{2(g)} \longleftrightarrow CS_{2(g)} + 2H_2S_{(g)}$
$(iii)$ $CO_{2(g)} + C_{(s)} \longleftrightarrow 2CO_{(g)}$
$(iv)$ $2H_{2(g)} + CO_{(g)} \longleftrightarrow CH_3OH_{(g)}$
$(v)$ $CaCO_{3(s)} \longleftrightarrow CaO_{(s)} + CO_{2(g)}$
$(vi)$ $4NH_{3(g)} + 5O_{2(g)} \longleftrightarrow 4NO_{(g)} + 6H_2O_{(g)}$

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(A) According to Le Chatelier's principle,increasing the pressure shifts the equilibrium toward the side with fewer moles of gaseous species.
$(i)$ $\Delta n_g = (1+1) - 1 = 1$. Pressure increase shifts it backward.
$(ii)$ $\Delta n_g = (1+2) - (1+2) = 0$. No effect.
$(iii)$ $\Delta n_g = 2 - 1 = 1$. Pressure increase shifts it backward.
$(iv)$ $\Delta n_g = 1 - (2+1) = -2$. Pressure increase shifts it forward.
$(v)$ $\Delta n_g = 1 - 0 = 1$. Pressure increase shifts it backward.
$(vi)$ $\Delta n_g = (4+6) - (4+5) = 1$. Pressure increase shifts it backward.

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