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(A) Reaction $(A)$ is a Friedel-Crafts acylation reaction where benzene reacts with benzoyl chloride in the presence of anhydrous $AlCl_3$ to form ben

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$A$ and $C$ only

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(A) Reaction $(A)$ is a Friedel-Crafts acylation reaction where benzene reacts with benzoyl chloride in the presence of anhydrous $AlCl_3$ to form benzophenone $(C_6H_5COC_6H_5)$.Reaction $(B)$ involves the reaction of benzoyl chloride with excess phenylmagnesium bromide followed by hydrolysis,which yields triphenylmethanol $( (C_6H_5)_3COH )$.Reaction $(C)$ involves the reaction of benzoyl chloride with diphenyl cadmium $( (C_6H_5)_2Cd )$,which is a standard method to prepare ketones from acid chlorides,yielding benzophenone.Therefore,reactions $(A)$ and $(C)$ produce benzophenone as the major product.

Which of the following reactions will give benzophenone as the major product?
$(A)$ Benzoyl chloride $+$ Benzene $+ AlCl_3$ (anhydrous)
$(B)$ Benzoyl chloride $+$ Phenylmagnesium bromide (excess)
$(C)$ Benzoyl chloride $+$ Diphenyl cadmium

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Which of the following reactions will give benzophenone as the major product?$(A)$ Benzoyl chloride $+$ Benzene $+ AlCl_3$ (anhydrous)$(B)$ Benzoyl chloride $+$ Phenylmagnesium bromide (excess)$(C)$ Benzoyl chloride $+$ Diphenyl cadmium