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(C) racemic mixture is produced when a chiral center is generated in a reaction,and both enantiomers are formed in equal amounts.$A$. $CH_3-CH(CH_3)-C

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(C) racemic mixture is produced when a chiral center is generated in a reaction,and both enantiomers are formed in equal amounts.$A$. $CH_3-CH(CH_3)-CH=CH_2 + HCl \rightarrow$ The carbocation formed undergoes rearrangement to form a stable tertiary carbocation,which upon attack by $Cl^-$ produces a chiral center,resulting in a racemic mixture.$B$. $CH_3-CO-CH_2-CH_3 + HCN \rightarrow$ The addition of $HCN$ to the carbonyl group creates a chiral center at the carbon atom,resulting in a racemic mixture of cyanohydrins.$C$. The reaction of $3$-methylcyclohex-$1$-ene with $HCl$ involves the formation of a carbocation at the $C-1$ position. The carbocation is planar,and the attack of $Cl^-$ can occur from either side,but due to the existing chiral center at $C-3$,the products formed are diastereomers,not a racemic mixture.$D$. $CH_3-CH_2-CH=CH_2 + HBr \rightarrow$ The addition of $HBr$ creates a chiral center at the $C-2$ position,resulting in a racemic mixture.

Which of the following reactions will not produce a racemic product?

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