Which of the following reactions will yield 2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of propyne $(CH_3C \equiv CH)$ with two equivalents of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ a

Vedclass · Accepted Answer

$CH_3C \equiv CH + 2HBr \rightarrow$

Vedclass · Answer

(B) The reaction of propyne $(CH_3C \equiv CH)$ with two equivalents of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ adds to the triple bond to form $2-$bromopropene $(CH_3C(Br)=CH_2)$. In the second step,another molecule of $HBr$ adds to the double bond,again following Markovnikov's rule,to yield $2, 2-$dibromopropane $(CH_3C(Br)_2CH_3)$.

Which of the following reactions will yield $2, 2-$dibromopropane?

Similar Questions

For the reaction $R - CH_2 - CCl_2 - R \xrightarrow{?} R - C \equiv C - R$,the suitable reagent is........

Which of the following metal carbides gives propyne on hydrolysis?

$2-$pentyne on reaction with sodium in liquid ammonia produces compound $A$. What is $A$?

In the given reaction $x$ is:
$CH_3 - C \equiv CH$ $\xrightarrow{Excess\ HCl} (A)$ $\xrightarrow{H_2O/OH^{-}} (x)$

$CH_3-C \equiv C-CH_3 \xrightarrow{\text{Cold } KMnO_4} (A)$
Product $(A)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module