Which of the following reagents would carry out the following transformation?
$C_6H_5COCH_3 \rightarrow C_6H_5CH(OD)CH_3$ (Note: The product shows a deuterium atom attached to the chiral carbon,not the oxygen).
$C_6H_5COCH_3 \rightarrow C_6H_5CH(OD)CH_3$ (Note: The product shows a deuterium atom attached to the chiral carbon,not the oxygen).
- A$NaBD_4$ in $CH_3OH$
- B$LiAlH_4$,then $D_2O$
- C$NaBD_4$ in $CH_3OD$
- D$LiAlD_4$,then $D_2O$
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Similar Questions
If the general formula of oxime and semicarbazone is $C=N-Z$,what is '$Z$' in oxime $(I)$ and semicarbazone $(II)$?
Match the following reagents with the products obtained when they react with a ketone.
List-$I$ List-$II$ $A. \ C_6H_5NHNH_2$ $I. \ \text{Schiff base}$ $B. \ NH_2OH$ $II. \ \text{Hydrazone}$ $C. \ C_6H_5NH_2$ $III. \ \text{Oxime}$ $IV. \ \text{Phenyl hydrazone}$
Correct answer is:
| List-$I$ | List-$II$ |
|---|---|
| $A. \ C_6H_5NHNH_2$ | $I. \ \text{Schiff base}$ |
| $B. \ NH_2OH$ | $II. \ \text{Hydrazone}$ |
| $C. \ C_6H_5NH_2$ | $III. \ \text{Oxime}$ |
| $IV. \ \text{Phenyl hydrazone}$ |
Correct answer is:
$CH_3CHO$ $\xrightarrow[5\,^{\circ}C]{10\%\,NaOH}$ $\xrightarrow[\Delta]{}$ $\xrightarrow[Ni]{H_2} (A)$; Product $(A)$ of the reaction is
Difficult
View SolutionProvide the chemical conversion for the following:
$(i)$ $3-$phenylprop$-2-$enal from Benzaldehyde and Ethanal (Cross-Aldol Condensation).
$(ii)$ Benzyl alcohol from Benzene.
$(i)$ $3-$phenylprop$-2-$enal from Benzaldehyde and Ethanal (Cross-Aldol Condensation).
$(ii)$ Benzyl alcohol from Benzene.
Medium
View Solution$2Ph-CHO \xrightarrow{OH^-} Ph-CH_2OH + PhCOO^-$
Which is the slowest step in the above Cannizzaro reaction?
Which is the slowest step in the above Cannizzaro reaction?
Medium
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