Which of the following relations is possible?

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(B) For any real angle $	heta$:$1$. The range of $\sin 	heta$ and $\cos 	heta$ is $[-1, 1]$. Thus,$\sin 	heta = \frac{5}{3} > 1$ is impossible.$2$

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$	an 	heta = 1002$

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(B) For any real angle $	heta$:$1$. The range of $\sin 	heta$ and $\cos 	heta$ is $[-1, 1]$. Thus,$\sin 	heta = \frac{5}{3} > 1$ is impossible.$2$. The range of $\sec 	heta$ is $(-\infty, -1] \cup [1, \infty)$. Thus,$\sec 	heta = \frac{1}{2}$ is impossible because $\frac{1}{2} $3$. For $\cos 	heta = \frac{1 + p^2}{1 - p^2}$,let $p = 2$. Then $\cos 	heta = \frac{1+4}{1-4} = \frac{5}{-3} = -1.66$,which is less than $-1$,so it is impossible.$4$. The range of $	an 	heta$ is $(-\infty, \infty)$. Therefore,$	an 	heta = 1002$ is possible.

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