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(D) For a $4d$ electron: $n = 4$ (principal quantum number). For a $d$ orbital,the azimuthal quantum number $l = 2$. The magnetic quantum number $m_l$

Vedclass · Accepted Answer

$n=4, l=2, m_l=1, m_s=-\frac{1}{2}$

Vedclass · Answer

(D) For a $4d$ electron: $n = 4$ (principal quantum number). For a $d$ orbital,the azimuthal quantum number $l = 2$. The magnetic quantum number $m_l$ can take values from $-l$ to $+l$,i.e.,$-2, -1, 0, +1, +2$. The spin quantum number $m_s$ can be $+\frac{1}{2}$ or $-\frac{1}{2}$. Comparing this with the given options,option $D$ $(n=4, l=2, m_l=1, m_s=-\frac{1}{2})$ is a valid set of quantum numbers for a $4d$ electron.

Which of the following represents the correct set of the four quantum numbers for a $4d$ electron?

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