Which of the following sequences is correct for the decreasing order of ionic radius?

  • A
    $I^{-} > Se^{2-} > Br^{-} > O^{2-} > F^{-}$
  • B
    $Se^{2-} > I^{-} > Br^{-} > F^{-} > O^{2-}$
  • C
    $I^{-} > Se^{2-} > O^{2-} > Br^{-} > F^{-}$
  • D
    $Se^{2-} > I^{-} > Br^{-} > O^{2-} > F^{-}$

Explore More

Similar Questions

Ionic sizes increase in the order :-

Which of the following ions has the smallest radius?

How does atomic radius vary in a period and in a group? How do you explain the variation?

Difficult
View Solution

Which of the following is the correct increasing order of ionic radii for $N^{3-}$,$Na^+$,$F^-$,$O^{2-}$,and $Mg^{2+}$?

Assertion: The atomic radius of gallium is higher than that of aluminium.
Reason: The presence of additional $d$-electrons offers poor screening effect for the outer electrons from increased nuclear charge.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo