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(A) The paramagnetic property of an ion is directly proportional to the number of unpaired electrons present in its $d$-orbitals. Let us calculate the

Vedclass · Accepted Answer

$Cu^{2+} < V^{2+} < Cr^{2+} < Mn^{2+}$

Vedclass · Answer

(A) The paramagnetic property of an ion is directly proportional to the number of unpaired electrons present in its $d$-orbitals. Let us calculate the number of unpaired electrons for each ion:    $Cu^{2+}$ $([Ar]3d^9)$ $1$ unpaired electron   $V^{2+}$ $([Ar]3d^3)$ $3$ unpaired electrons   $Cr^{2+}$ $([Ar]3d^4)$ $4$ unpaired electrons   $Mn^{2+}$ $([Ar]3d^5)$ $5$ unpaired electrons    Arranging them in increasing order of unpaired electrons: $1 Therefore,the correct order is $Cu^{2+} < V^{2+} < Cr^{2+} < Mn^{2+}$.

Which of the following sets correctly represents the increasing order of the paramagnetic property of the ions?

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