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(B) $I$. Acidity: The presence of electron-withdrawing groups ($-I$ effect) increases the acidity of carboxylic acids,while electron-donating groups (

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$I, III$ only

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(B) $I$. Acidity: The presence of electron-withdrawing groups ($-I$ effect) increases the acidity of carboxylic acids,while electron-donating groups ($+I$ effect or hyperconjugation) decrease it. The order $NCCH_2COOH > FCH_2COOH > H_3CCH_2COOH$ is correct because $-CN$ has a stronger $-I$ effect than $-F$,and $-CH_3$ is electron-donating.$II$. Reactivity (towards nucleophilic addition): Aldehydes are generally more reactive than ketones due to less steric hindrance and electronic factors. Among aldehydes,$CH_3CH_2CHO$ is more reactive than $PhCHO$ (due to resonance stabilization of the carbonyl group by the phenyl ring). Thus,the correct order is $CH_3CH_2CHO > PhCHO > PhCOCH_3$. The given order is incorrect.$III$. Boiling points: Alcohols have the highest boiling points due to intermolecular hydrogen bonding. Among carbonyl compounds of similar molecular weight,aldehydes generally have higher boiling points than ketones due to greater dipole-dipole interactions and less steric hindrance. The order $H_3COCH_2CH_3$ (ketone) $Therefore,sets $I$ and $III$ are correct.

Sets	Property
$I$. $NCCH_2COOH > FCH_2COOH > H_3CCH_2COOH$	Acidity
$II$. $CH_3CH_2CHO > PhCOCH_3 > PhCHO$	Reactivity
$III$. $H_3COCH_2CH_3 < H_3CCH_2CHO < H_3CCH_2CH_2OH$	Boiling points

Which of the following sets is in the correct order regarding the property mentioned against them?
Sets Property
$I$. $NCCH_2COOH > FCH_2COOH > H_3CCH_2COOH$ Acidity
$II$. $CH_3CH_2CHO > PhCOCH_3 > PhCHO$ Reactivity
$III$. $H_3COCH_2CH_3 < H_3CCH_2CHO < H_3CCH_2CH_2OH$ Boiling points

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Which of the following sets is in the correct order regarding the property mentioned against them?SetsProperty$I$. $NCCH_2COOH > FCH_2COOH > H_3CCH_2COOH$Acidity$II$. $CH_3CH_2CHO > PhCOCH_3 > PhCHO$Reactivity$III$. $H_3COCH_2CH_3 < H_3CCH_2CHO < H_3CCH_2CH_2OH$Boiling points