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(D) The depression in freezing point is given by the formula $\Delta T_f = i 	imes K_f 	imes m$,where $i$ is the van't Hoff factor,$K_f$ is the cryo

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$1\, m\, C_{12}H_{22}O_{11}$

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(D) The depression in freezing point is given by the formula $\Delta T_f = i 	imes K_f 	imes m$,where $i$ is the van't Hoff factor,$K_f$ is the cryoscopic constant,and $m$ is the molality.Since $K_f$ and $m$ are constant for all solutions,the depression in freezing point depends on the van't Hoff factor $(i)$.Freezing point $T_f = T_f^0 - \Delta T_f$. To have the maximum freezing point,the depression $\Delta T_f$ must be minimum,which means $i$ must be minimum.Let us calculate $i$ for each solute:$(A)$ $CH_3COONa ightarrow CH_3COO^- + Na^+$,$i = 2$$(B)$ $CaCl_2 ightarrow Ca^{2+} + 2Cl^-$,$i = 3$$(C)$ $Na_3PO_4 ightarrow 3Na^+ + PO_4^{3-}$,$i = 4$$(D)$ $C_{12}H_{22}O_{11}$ (sucrose) is a non-electrolyte,$i = 1$Since $C_{12}H_{22}O_{11}$ has the smallest $i$ value,it will have the minimum depression in freezing point and thus the maximum freezing point.

Which of the following solutions has the maximum freezing point?

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