Which of the following solutions has osmotic | vedclass

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(C) Osmotic pressure $(\pi)$ is a colligative property and is given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar co

Vedclass · Accepted Answer

$Al_2(SO_4)_3$

Vedclass · Answer

(C) Osmotic pressure $(\pi)$ is a colligative property and is given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar concentration,$R$ is the gas constant,and $T$ is the temperature.For equimolar solutions ($C$ is constant) at the same temperature,the osmotic pressure depends directly on the van't Hoff factor $(i)$.For $K_4[Fe(CN)_6]$,it dissociates as $K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}$,so $i = 4 + 1 = 5$.Now,let's calculate $i$ for the options:$(A)$ $Na_2SO_4 \rightarrow 2Na^+ + SO_4^{2-}$,$i = 3$.$(B)$ $BaCl_2 \rightarrow Ba^{2+} + 2Cl^-$,$i = 3$.$(C)$ $Al_2(SO_4)_3 \rightarrow 2Al^{3+} + 3SO_4^{2-}$,$i = 2 + 3 = 5$.$(D)$ $C_{12}H_{22}O_{11}$ (sucrose) is a non-electrolyte,so $i = 1$.Since $Al_2(SO_4)_3$ has the same van't Hoff factor $(i = 5)$ as $K_4[Fe(CN)_6]$,it will have the same osmotic pressure.

Which of the following solutions has osmotic pressure nearer to that of an equimolar solution of $K_4[Fe(CN)_6]$?

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