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(C) The amount of solute in grams is calculated using the formula: $	ext{Mass} = 	ext{Molarity} (M) 	imes 	ext{Volume} (V 	ext{ in } L) 	imes

Vedclass · Accepted Answer

$C$. $0.5 \ L$ of $1.0 \ M \ KMnO_4$ $(158 \ u)$

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(C) The amount of solute in grams is calculated using the formula: $	ext{Mass} = 	ext{Molarity} (M) 	imes 	ext{Volume} (V 	ext{ in } L) 	imes 	ext{Molar Mass} (MW)$.For $A$: $	ext{Mass} = 0.25 	imes 1.0 	imes 106 = 26.5 \ g$.For $B$: $	ext{Mass} = 0.2 	imes 0.25 	imes 142 = 7.1 \ g$.For $C$: $	ext{Mass} = 1.0 	imes 0.5 	imes 158 = 79.0 \ g$.For $D$: $	ext{Mass} = 0.5 	imes 0.75 	imes 60 = 22.5 \ g$.Comparing the values, $79.0 \ g$ is the highest amount. Therefore, option $C$ is correct.

Which of the following solutions has the highest amount of solute (in grams)?

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