Which of the following species is paramagneti | vedclass

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(C) $1$. $K_3[Co(C_2O_4)_3]$ contains $[Co(C_2O_4)_3]^{3-}$. Here,$Co^{3+}$ is in $d^6$ configuration. With strong field ligand $C_2O_4^{2-}$,it is di

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$[NMe_4]O_3$

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(C) $1$. $K_3[Co(C_2O_4)_3]$ contains $[Co(C_2O_4)_3]^{3-}$. Here,$Co^{3+}$ is in $d^6$ configuration. With strong field ligand $C_2O_4^{2-}$,it is diamagnetic.$2$. $NO[PF_6]$ consists of $NO^+$ and $[PF_6]^-$. $NO^+$ has $14$ electrons (isoelectronic with $N_2$),so it is diamagnetic. $[PF_6]^-$ is also diamagnetic.$3$. $[NMe_4]O_3$ consists of $[NMe_4]^+$ and $O_3^-$. The ozonide ion $O_3^-$ has $19$ valence electrons,making it paramagnetic due to an unpaired electron.$4$. $H[BF_4]$ consists of $H^+$ and $[BF_4]^-$. Both are diamagnetic.Thus,$[NMe_4]O_3$ is the paramagnetic species.

Which of the following species is paramagnetic?

Similar Questions

Among the following complexes,the total number of diamagnetic species is. . . . $[Mn(NH_3)_6]^{3+}, [MnCl_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Fe(NH_3)_6]^{3+}$ and $[Co(en)_3]^{3+}$
[Given,atomic number: $Mn=25, Fe=26, Co=27$; $en=H_2NCH_2CH_2NH_2$ ]

The correct order of magnetic moments (spin-only values in $B.M.$) among the following is:
(Atomic numbers: $Mn = 25, Fe = 26, Co = 27$)

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