Which of the following statements is correct?

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(D) Option $(A)$ is incorrect because a charged particle entering a magnetic field at an angle other than $90^o$ follows a helical path,not a circular

Vedclass · Accepted Answer

Both $(B)$ and $(C)$

Vedclass · Answer

(D) Option $(A)$ is incorrect because a charged particle entering a magnetic field at an angle other than $90^o$ follows a helical path,not a circular one.Option $(B)$ is correct. When a charged particle enters a uniform magnetic field perpendicular to its velocity,it experiences a magnetic force $F = q(v 	imes B)$ which acts as a centripetal force,causing the particle to move in a circular path. Both the electron and proton will follow circular paths.Option $(C)$ is correct. The magnetic force acting on a moving charged particle is always perpendicular to its velocity $(F = q(v 	imes B))$. Since the force is perpendicular to the displacement,the work done by the magnetic force is zero $(W = F \cdot ds = 0)$. According to the work-energy theorem,the kinetic energy of the particle remains constant.Since both $(B)$ and $(C)$ are correct,option $(D)$ is the correct answer.

List-$I$	List-$II$
$(A)$ Permeability of free space	$(I) \ [M L^2 T^{-2}]$
$(B)$ Magnetic field	$(II) \ [M T^{-2} A^{-1}]$
$(C)$ Magnetic moment	$(III) \ [M L T^{-2} A^{-2}]$
$(D)$ Torsional constant	$(IV) \ [L^2 A]$

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