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(C) According to $MOT$,the electronic configuration of the peroxide ion $(O_2^{2-})$ is:$\sigma_{1s}^{2} \sigma_{1s}^{*2} \sigma_{2s}^{2} \sigma_{2s}^

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$A, B, C$

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(C) According to $MOT$,the electronic configuration of the peroxide ion $(O_2^{2-})$ is:$\sigma_{1s}^{2} \sigma_{1s}^{*2} \sigma_{2s}^{2} \sigma_{2s}^{*2} \sigma_{2pz}^{2} \pi_{2px}^{2} = \pi_{2py}^{2} \pi_{2px}^{*2} = \pi_{2py}^{*2}$$1$. The antibonding molecular orbitals $(\sigma_{1s}^{*}, \sigma_{2s}^{*}, \pi_{2px}^{*}, \pi_{2py}^{*})$ are completely filled. Thus,statement $A$ is correct.$2$. Since all electrons are paired,the ion is diamagnetic. Thus,statement $B$ is correct.$3$. Bond order $(B.O.)$ $= \frac{N_b - N_a}{2} = \frac{10 - 8}{2} = 1.0$. Thus,statement $C$ is correct.$4$. The total number of electrons in $O_2^{2-}$ is $8 + 8 + 2 = 18$,whereas Neon has $10$ electrons. Thus,statement $D$ is incorrect.Therefore,statements $A, B,$ and $C$ are correct.

Which of the following statements is correct for the peroxide ion $(O_2^{2-})$?
$A.$ It has completely filled antibonding molecular orbitals.
$B.$ It is diamagnetic.
$C.$ It has a bond order of $1$.
$D.$ It is isoelectronic with Neon.

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Which of the following statements is correct for the peroxide ion $(O_2^{2-})$?$A.$ It has completely filled antibonding molecular orbitals.$B.$ It is diamagnetic.$C.$ It has a bond order of $1$.$D.$ It is isoelectronic with Neon.