Which of the following statements is correct?

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(D) In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$ ($3d^6$ configuration). $F^-$ is a weak field ligand,so it forms an outer orbital complex ($

Vedclass · Accepted Answer

$[CoF_6]^{3-}$ is outer orbital complex while $[Co(NH_3)_6]^{3+}$ is inner orbital complex

Vedclass · Answer

(D) In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$ ($3d^6$ configuration). $F^-$ is a weak field ligand,so it forms an outer orbital complex ($sp^3d^2$ hybridization) which is paramagnetic with $4$ unpaired electrons.In $[Co(NH_3)_6]^{3+}$,the oxidation state of $Co$ is $+3$ ($3d^6$ configuration). $NH_3$ is a strong field ligand,so it causes pairing of electrons,forming an inner orbital complex ($d^2sp^3$ hybridization) which is diamagnetic.Therefore,statement $D$ is correct: $[CoF_6]^{3-}$ is an outer orbital complex while $[Co(NH_3)_6]^{3+}$ is an inner orbital complex.

List-$I$	List-$II$
$A. K_2[Ni(CN)_4]$	$I. sp^3$
$B. [Ni(CO)_4]$	$II. sp^3d^2$
$C. [Co(NH_3)_6]Cl_3$	$III. dsp^2$
$D. Na_3[CoF_6]$	$IV. d^2sp^3$

Similar Questions

Explain Valence Bond Theory.

The coordination environment of $Ca^{2+}$ ion in its complex with $EDTA^{4-}$ is:

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A. K_2[Ni(CN)_4]$ $I. sp^3$

$B. [Ni(CO)_4]$ $II. sp^3d^2$

$C. [Co(NH_3)_6]Cl_3$ $III. dsp^2$

$D. Na_3[CoF_6]$ $IV. d^2sp^3$

Choose the correct answer from the options given below:

The number of unpaired electrons responsible for the paramagnetic nature of the following complex species are respectively $:$
$[Fe(CN)_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Mn(CN)_6]^{3-}$

For the coordination compound $[Co(NH_3)_5CO_3]ClO_4$,what are the coordination number,oxidation state,number of electrons in the $d$-orbitals,and the number of unpaired electrons for the central metal $Co$?

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