Which of the following statements is correct | vedclass

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(A) The equivalent weight of an oxidizing agent is given by $\frac{	ext{Molecular Weight}}{n	ext{-factor}}$.In an alkaline medium,$KMnO_4$ acts as a

Vedclass · Accepted Answer

It is one third of its molecular weight in alkaline medium

Vedclass · Answer

(A) The equivalent weight of an oxidizing agent is given by $\frac{	ext{Molecular Weight}}{n	ext{-factor}}$.In an alkaline medium,$KMnO_4$ acts as an oxidizing agent and undergoes the following change: $MnO_4^- + 2H_2O + 3e^- ightarrow MnO_2 + 4OH^-$.The change in oxidation state of $Mn$ is from $+7$ to $+4$,so the $n$-factor is $3$.Therefore,the equivalent weight in an alkaline medium is $\frac{M}{3}$.Thus,the correct statement is that it is one third of its molecular weight in an alkaline medium.

Which of the following statements is correct about the equivalent weight of $KMnO_4$?

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