(C) Reducing power decreases from $SO_2$ to $TeO_2$ on moving down the group.$(B)$ The order of boiling points of hydrides of $16^{\text{th}}$ group e

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Rhombic sulphur has $S_8$ molecules while monoclinic sulphur has $S_6$ molecules.

(C) Reducing power decreases from $SO_2$ to $TeO_2$ on moving down the group.$(B)$ The order of boiling points of hydrides of $16^{\text{th}}$ group elements is $H_2S $(C)$ Both rhombic and monoclinic sulphur contain $S_8$ molecules. Therefore,statement $(C)$ is incorrect.$(D)$ The bond angle of ozone is $117^{\circ}$.Thus,option $(C)$ is the incorrect statement.

Class 12 Chemistry p-Block Elements (Class 12)Oxygen family

Medium

Which of the following statements is not correct?

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A
From $SO_2$ to $TeO_2$ reducing power decreases.
B
The order of boiling points of hydrides of $16^{\text{th}}$ group elements is $H_2S < H_2Se < H_2Te < H_2O$.
C
Rhombic sulphur has $S_8$ molecules while monoclinic sulphur has $S_6$ molecules.
D
The bond angle in ozone molecule is $117^{\circ}$.