Which of the following will have maximum stab | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The crystal field stabilization energy $(CFSE)$ depends on the nature of the ligand and the oxidation state of the metal ion.
$CN^-$ is a strong

Vedclass · Accepted Answer

$[Co(CN)_6]^{3-}$

Vedclass · Answer

(C) The crystal field stabilization energy $(CFSE)$ depends on the nature of the ligand and the oxidation state of the metal ion.
$CN^-$ is a strong field ligand,which causes a large splitting of $d$-orbitals $(\Delta_o)$.
In $[Co(CN)_6]^{3-}$,$Co$ is in the $+3$ oxidation state ($d^6$ configuration).
Since $CN^-$ is a strong field ligand,it leads to a low-spin $t_{2g}^6 e_g^0$ configuration,resulting in a very high $CFSE$ value compared to the other complexes listed,which involve weak field ligands like $H_2O$ or have lower oxidation states.

Which of the following will have maximum stabilization due to crystal field?

Similar Questions

The energies of $d_{xy}$ and $d_{z^2}$-orbitals in octahedral and tetrahedral transition metal complexes are such that

In the spectrochemical series, the positions occupied by the ligands $Cl^{-}$, $OH^{-}$, and $CN^{-}$ in increasing order of their crystal field splitting power are:

Which one is correct for a high spin complex?

The electronic spectrum of $[Ti(H_2O)_6]^{3+}$ gives a single broad peak with a maxima at $20300 \, cm^{-1}$. The crystal field stabilization energy is equal to .......... $kJ \, mol^{-1}$

Which of the following cannot be explained by crystal field theory?

Vedclass Test Series

Exam Paper Generator

Online Exam Module