Which of the following will show geometrical | vedclass

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Question

(A) For a molecule to exhibit geometrical isomerism,each carbon atom of the double bond must be attached to two different groups. In $CH_3-CH=CH-CH_3$

Vedclass · Accepted Answer

$CH_3-CH=CH-CH_3$

Vedclass · Answer

(A) For a molecule to exhibit geometrical isomerism,each carbon atom of the double bond must be attached to two different groups. In $CH_3-CH=CH-CH_3$ (but$-2-$ene),each carbon of the double bond is attached to a hydrogen atom and a methyl group. Thus,it exists as cis and trans isomers. In $(CH_3)_2C=C(CH_3)_2$,each carbon is attached to two identical methyl groups,so it does not show geometrical isomerism. In $CH_3-CH=C(CH_3)_2$,one carbon is attached to two identical methyl groups,so it does not show geometrical isomerism. Therefore,the correct option is $A$.

Which of the following will show geometrical isomerism?

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