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(D) Given the matrix equation: $\left[\begin{array}{cc}3x+7 & 5 \ y+1 & 2-3x\end{array}ight]=\left[\begin{array}{cc}0 & y-2 \ 8 & 4\end{array}ig

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(D) Given the matrix equation: $\left[\begin{array}{cc}3x+7 & 5 \ y+1 & 2-3x\end{array}ight]=\left[\begin{array}{cc}0 & y-2 \ 8 & 4\end{array}ight]$By equating the corresponding elements,we obtain the following equations:$1$. $3x+7=0 \Rightarrow 3x=-7 \Rightarrow x=-\frac{7}{3}$$2$. $5=y-2 \Rightarrow y=7$$3$. $y+1=8 \Rightarrow y=7$$4$. $2-3x=4 \Rightarrow -3x=2 \Rightarrow x=-\frac{2}{3}$Comparing the results,we observe that the value of $x$ obtained from the first element is $-\frac{7}{3}$,while the value of $x$ obtained from the fourth element is $-\frac{2}{3}$.Since a single variable $x$ cannot take two different values simultaneously,it is not possible to find values of $x$ and $y$ that satisfy the equality of these two matrices.

Which of the given values of $x$ and $y$ make the following pair of matrices equal?
$\left[\begin{array}{cc}3x+7 & 5 \\ y+1 & 2-3x\end{array}\right]=\left[\begin{array}{cc}0 & y-2 \\ 8 & 4\end{array}\right]$

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Which of the given values of $x$ and $y$ make the following pair of matrices equal?$\left[\begin{array}{cc}3x+7 & 5 \\ y+1 & 2-3x\end{array}\right]=\left[\begin{array}{cc}0 & y-2 \\ 8 & 4\end{array}\right]$