Which of these will produce the highest yield | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The Friedel-Crafts reaction is an electrophilic aromatic substitution. It requires an activated or moderately deactivated aromatic ring. $1$. $Ben

Vedclass · Accepted Answer

Chlorobenzene

Vedclass · Answer

(C) The Friedel-Crafts reaction is an electrophilic aromatic substitution. It requires an activated or moderately deactivated aromatic ring. $1$. $Benzamide$ has a strongly electron-withdrawing $-CONH_2$ group,which deactivates the ring. $2$. $Aniline$ $(-NH_2)$ and $Phenol$ $(-OH)$ contain lone pairs that react with the Lewis acid catalyst $(AlCl_3)$ to form a complex,which strongly deactivates the ring and prevents the reaction. $3$. $Chlorobenzene$ is a deactivated ring due to the $-I$ effect of the chlorine atom,but it is still capable of undergoing Friedel-Crafts reactions,unlike the other options which are either strongly deactivated or form complexes with the catalyst. Therefore,among the given choices,$Chlorobenzene$ will produce the highest yield.

Which of these will produce the highest yield in a Friedel-Crafts reaction?

Similar Questions

How many products are capable of being formed from toluene in each of the following reactions shown in the figure?

What are the various steps of electrophilic substitution of benzene?

Predict the product of the following reaction sequence:
$1$. Benzene + $CH_3CH_2CH_2COCl / AlCl_3$
$2$. $Zn(Hg), HCl$
$3$. $Br_2, FeBr_3$

Predict the major product of the reaction of $1$-ethyl-$3$-methylbenzene with $KMnO_4$ in an acidic medium under heating.

What is the correct order of decreasing reactivity for the monobromination of the following compounds?

Vedclass Test Series

Exam Paper Generator

Online Exam Module