Which one has the highest coagulation power?

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Question

(D) According to the Hardy-Schulze rule,the coagulation power of an ion is directly proportional to the magnitude of its charge.Greater the valence of

Vedclass · Accepted Answer

$Sn^{4+}$

Vedclass · Answer

(D) According to the Hardy-Schulze rule,the coagulation power of an ion is directly proportional to the magnitude of its charge.Greater the valence of the flocculating ion added,the greater is its power to cause precipitation.Comparing the charges: $K^{+}$ $(+1)$,$Ca^{2+}$ $(+2)$,$Al^{3+}$ $(+3)$,$Sn^{4+}$ $(+4)$.Since $Sn^{4+}$ has the highest charge $(+4)$,it possesses the highest coagulation power.

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