Which one of the following compounds will not | vedclass

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(C) Sodium bicarbonate $(NaHCO_3)$ is a weak base. Only acids stronger than carbonic acid $(H_2CO_3)$ can react with it to evolve $CO_2$ gas and becom

Vedclass · Accepted Answer

$o-$Nitrophenol

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(C) Sodium bicarbonate $(NaHCO_3)$ is a weak base. Only acids stronger than carbonic acid $(H_2CO_3)$ can react with it to evolve $CO_2$ gas and become soluble.$2, 4, 6-$Trinitrophenol (picric acid),benzoic acid,and benzene sulphonic acid are stronger acids than carbonic acid and are soluble in $NaHCO_3$.$o-$Nitrophenol is a weaker acid than carbonic acid. Additionally,it forms intramolecular hydrogen bonding between the $-OH$ group and the $-NO_2$ group,which makes the acidic proton less available for reaction with the base. Therefore,it is not soluble in sodium bicarbonate.

List-$I$ (Compound)	List-$II$ $(pK_a)$
$A$. $p-$Nitrophenol	$I$. $7.1$
$B$. Phenol	$II$. $10.0$
$C$. Ethanol	$III$. $15.9$
$D$. $p-$Cresol	$IV$. $10.2$

Which one of the following compounds will not be soluble in sodium bicarbonate?

Similar Questions

Match the following:
List-$I$ (Compound) List-$II$ $(pK_a)$
$A$. $p-$Nitrophenol $I$. $7.1$
$B$. Phenol $II$. $10.0$
$C$. Ethanol $III$. $15.9$
$D$. $p-$Cresol $IV$. $10.2$
The correct answer is

Which among the following is obtained as a product when phenol is treated with $NaOH$ and $CO_2$ followed by acid hydrolysis?

Which statement is incorrect for the product of the reaction shown above?

The conversion of $O$-acylated phenol in the presence of $AlCl_3$ to $C$-acylated phenol is an example of which type of organic reaction?

What is the product formed during the hydrogenation of phenol in the presence of a nickel catalyst at $160\,^oC$?

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