Which one of the following corresponds to a p | vedclass

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Question

(A) The energy of a photon is given by $E = h 
u = \frac{hc}{\lambda} = hc \cdot \bar{
u}$, where $\bar{
u} = \frac{1}{\lambda}$.For option $(A)$:

Vedclass · Accepted Answer

$\lambda = 300 \ nm$

Vedclass · Answer

(A) The energy of a photon is given by $E = h 
u = \frac{hc}{\lambda} = hc \cdot \bar{
u}$, where $\bar{
u} = \frac{1}{\lambda}$.For option $(A)$: $\lambda = 300 \ nm = 300 	imes 10^{-9} \ m$. $E = \frac{(6.626 	imes 10^{-34} \ J \cdot s)(3 	imes 10^{8} \ m/s)}{300 	imes 10^{-9} \ m} = 6.626 	imes 10^{-19} \ J$.For option $(B)$: $
u = 3 	imes 10^{4} \ s^{-1}$. $E = h 
u = (6.626 	imes 10^{-34} \ J \cdot s)(3 	imes 10^{4} \ s^{-1}) = 1.9878 	imes 10^{-29} \ J$.For option $(C)$: $\bar{
u} = 30 \ cm^{-1} = 3000 \ m^{-1}$. $E = hc \cdot \bar{
u} = (6.626 	imes 10^{-34} \ J \cdot s)(3 	imes 10^{8} \ m/s)(3000 \ m^{-1}) = 5.9634 	imes 10^{-22} \ J$.For option $(D)$: $E = 6.626 	imes 10^{-27} \ J$.Comparing the values, the energy in option $(A)$ is the highest.

Metal	$Li, Na, K, Mg, Cu, Ag, Fe, Pt, W$
$\phi \ (eV)$	$2.4, 2.3, 2.2, 3.7, 4.8, 4.3, 4.7, 6.3, 4.75$

Which one of the following corresponds to a photon of highest energy?

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