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(C) For $Ti, V, Cr, Mn$,the number of oxidation states are $3, 4, 5, 6$ respectively. Thus,$Ti < V < Cr < Mn$ is correct.For magnetic moment $(\mu) =

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$Ti < V < Cr < Mn$; increasing melting points

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(C) For $Ti, V, Cr, Mn$,the number of oxidation states are $3, 4, 5, 6$ respectively. Thus,$Ti For magnetic moment $(\mu) = \sqrt{n(n+2)} \ B.M$:$Ti^{3+} (3d^1): n=1, \mu = \sqrt{3} \ B.M$$V^{3+} (3d^2): n=2, \mu = \sqrt{8} \ B.M$$Cr^{3+} (3d^3): n=3, \mu = \sqrt{15} \ B.M$$Mn^{3+} (3d^4): n=4, \mu = \sqrt{24} \ B.M$Thus,$Ti^{3+} The actual order of melting points is $Mn The $2^{nd}$ ionization enthalpy order is $Ti < V < Mn < Cr$,which is correct.

Which one of the following does not correctly represent the correct order of the property indicated against it?

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