Which one of the following has a potential mo | vedclass

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Question

(A) For the hydrogen electrode $Pt, \frac{1}{2} H_{2}(1 \ atm) \mid H^{+}(aq)$,the reduction potential is given by the Nernst equation: $E = E^{\circ}

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$Pt, \frac{1}{2} H_{2}(1 \ atm) \mid HCl(2 \ M)$

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(A) For the hydrogen electrode $Pt, \frac{1}{2} H_{2}(1 \ atm) \mid H^{+}(aq)$,the reduction potential is given by the Nernst equation: $E = E^{\circ} - \frac{0.0591}{1} \log \frac{1}{[H^{+}]}$ Since $E^{\circ} = 0 \ V$ for the Standard Hydrogen Electrode $(SHE)$,the equation simplifies to: $E = 0.0591 \log [H^{+}]$ For $HCl$ solutions,$[H^{+}] = [HCl]$. $(A)$ For $[HCl] = 2 \ M$: $E = 0.0591 \log(2) \approx 0.0591 	imes 0.3010 = 0.0178 \ V$ $(B)$ For $[HCl] = 0.1 \ M$: $E = 0.0591 \log(0.1) = 0.0591 	imes (-1) = -0.0591 \ V$ $(C)$ For $[HCl] = 0.5 \ M$: $E = 0.0591 \log(0.5) \approx 0.0591 	imes (-0.3010) = -0.0178 \ V$ $(D)$ For $[HCl] = 1 \ M$: $E = 0.0591 \log(1) = 0 \ V$ Thus,only the electrode in option $(A)$ has a potential greater than zero.

Which one of the following has a potential more than zero?

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