Which one of the following is an outer orbita | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the nature of the complexes,we analyze their electronic configurations and hybridization:$1$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8

Vedclass · Accepted Answer

$[Ni(NH_3)_6]^{2+}$

Vedclass · Answer

(A) To determine the nature of the complexes,we analyze their electronic configurations and hybridization:$1$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8$. It forms an outer orbital complex ($sp^3d^2$ hybridization) with $2$ unpaired electrons,making it paramagnetic.$2$. $[Zn(NH_3)_6]^{2+}$: $Zn^{2+}$ is $3d^{10}$. It is diamagnetic as there are no unpaired electrons.$3$. $[Cr(NH_3)_6]^{3+}$: $Cr^{3+}$ is $3d^3$. It forms an inner orbital complex ($d^2sp^3$ hybridization) and is paramagnetic,but it is not an outer orbital complex.$4$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. In the presence of strong field ligand $NH_3$,it forms an inner orbital complex ($d^2sp^3$ hybridization) and is diamagnetic.Therefore,$[Ni(NH_3)_6]^{2+}$ is the correct answer.

Which one of the following is an outer orbital complex and exhibits paramagnetic behavior?

Similar Questions

$A$ ball is projected with velocity $V_0$ at an angle of elevation $30^\circ$. Mark the correct statement.

$A$ graph of magnetic flux $(\phi)$ versus current $(I)$ is drawn for four inductors $A, B, C, D$. Which inductor has the largest value of self-inductance?

$\int \frac{dx}{a^2 \sin^2 x + b^2 \cos^2 x}$ is equal to

$A$ metal sphere of radius $r$ and specific heat $S$ is rotated about an axis passing through its centre at a speed of $n$ rotations per second. It is suddenly stopped and $50 \%$ of its energy is used in increasing its temperature. Then,the rise in temperature of the sphere is

Vedclass Test Series

Exam Paper Generator

Online Exam Module